4m^2-12m=27

Solution for 4m^2-12m=27 equation:

4m^2-12m=27

We move all terms to the left:

4m^2-12m-(27)=0

a = 4; b = -12; c = -27;
Δ = b2-4ac
Δ = -122-4·4·(-27)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-24}{2*4}=\frac{-12}{8}
=-1+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+24}{2*4}=\frac{36}{8}
=4+1/2
$